/* - two arrays contain the ages and the corresponding salaries
 -  a solution based on another task!!!
a.)  who is the oldest, and how old is he/she?
b.) who is older then 40 and earns less then 2000 EUR? 
c.) younger then 30 - give the indeces */


#include <iostream>


using namespace std;



int main()
{
     const int maxm=100;
     int age[maxm];
     int sal[maxm];
    
     int db;

    cout<<" nr. of data: "<<endl;

     cin>>db;

     cout<<" give the ages and salaries: "<<endl;

       for(int i=0;i<db;++i)
     {

         cin>>age[i]>>sal[i];
     }

     //a.- the oldest is:

    
      int maxind=0;
      int max_age=age[0];
     
     for (int i=1;i<db;++i)
    {
         if( max_age<age[i])
        {
           max_age=age[i];
           maxind=i;
         }
 }

cout<<" the oldest is: "<<max_age<<" old, at "<<maxind+1<<". "<<endl;


//b. above 40, earnS <2000

    int bdb=0;
    for (int i=0;i<db;++i)
    {
        if (age[i]>40 && sal[i]<200000)
        {
            bdb=bdb+1;
        }
    }

    cout<<" those who are older then 40 and earn less then 200 eFt.  "<<bdb<<endl;

//c.) younger then 30 - give the indeces
  


    return 0;
}